WebApr 4, 2024 · datediff () 函数返回两个日期之间的间隔,默认是间隔天数 datedi ff (datepart, date1, date2) date1:开始时间;date2:结束时间 举例如下: select dateadd (year, - 1, GETDATE ()) 开始日期,GETDATE () 结束日期, '前后2个时间相差' + convert (varchar ( 1 ),datediff (year, dateadd (year, - 1, GETDATE ()),GETDATE ())) + '年' type union all Web昨天的所有数据:select * from 表名 where DateDiff(dd,datetime类型字段,getdate())=1 7天内的所有数据:select * from 表名 where DateDiff(dd,datetime类型字段,getdate())<=7 …
Help me understand my DATEADD DATEDIFF formula - SQL Server …
WebMay 27, 2010 · First, take the inner DATEDIFF portion. SELECT DATEDIFF (dd,0,GETDATE ()) = 40234. What this portion is doing is figuring out the number of days … Web函数getdate()可以用来作为datedime型字段的缺省值。 这对插入记录时保存当时的时间是有用的。 要建立一个表,其中的记录包含有当前的日期和时间,可以添加一个DATETIME型字段,指定其缺省值为函数GETDATE()的返回值,就象这样: small bar for patio
sqlserver当月、时间_SQLServer日期函数大全 - 百度文库
WebJun 6, 2024 · Remove the outer DATEADD to leave SELECT DATEDIFF(month, -1, GETDATE()) which returns 1410. This is the number of date boundaries crossed (in this case months) since -1 to getdate(). Datetimes are stored as 2 4-byte integers which means we can actually use numerics to manipulate dates. Here we are using -1 and if you run … WebApr 13, 2024 · select GETDATE () as '当前日期时间', DATEDIFF (year,'2024-12-20 05:49:00', GetDate ()) as '年数之差', DATEDIFF ( quarter,'2024-03-20 05:49:00', GetDate ()) as '季度之差', DATEDIFF ( week,'2024-06-20 05:49:00', GetDate ()) as '周数之差', DATEDIFF (month,'2024-06-20 05:49:00', GetDate ()) as '月分之差', DATEDIFF ( … WebMar 4, 2024 · SELECT DATEADD(day, -1, DATEADD(month, DATEDIFF(month, 0, GETDATE()) + 1, 0)) 17. 获取当前周的第一天 solihull natural health group