WebApr 16, 2024 · The probability of rolling a specific number twice in a row is indeed 1/36, because you have a 1/6 chance of getting that number on each of two rolls (1/6 x 1/6).. … WebOct 20, 2024 · $\begingroup$ The expected value I calculated was using the example numbers above ie. 20 dice, a 50% chance of succss in round 1, a 66.6% chance of …
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http://mathcentral.uregina.ca/QQ/database/QQ.09.06/s/matt1.html WebJul 26, 2024 · 8 possibilities. Only one fits the criteria - so 1/8 chances of all heads. The pattern is (1/S)^n or (1/2)^3. For dice S = 6, and we have 6 of them. Probability of getting a 6 on any given roll is 1/6. Rolls are independent events. So using 2 dice getting all 6's is (1/6)* (1/6) or 1/36. (1/6)^6 is about 1 in 46,656. tcp_keepalive_time
What happens if you roll doubles 3 times then land on "Go to jail?"
WebJul 28, 2010 · Assuming that the die is a "normal" one (it has the numbers 1 to 6 and that it is fair), then the probability of rolling six three times in a row is 1/6*1/6*1/6 = 1/216 = 0.00463. The probability of rolling six three times in a row eventually is 1 (ie a certainty). Wiki User. ∙ 2010-07-28 16:10:33. WebJul 28, 2010 · Assuming that the die is a "normal" one (it has the numbers 1 to 6 and that it is fair), then the probability of rolling six three times in a row is 1/6*1/6*1/6 = 1/216 = … WebThe former would be the chance if the 98 chances to roll 3 6-6s in a row were independent. Since they tend to clump together, the probability is lower. Douglas Zare. Christofurcats 2003-07-17 16:54:35 UTC. Permalink. love reading all this mumbo-jumbo trying to make computer backgammon something tcp_miss/200